Question 813677
x^2+2x+4x+8=0
x[x^2/x+2x/x]+2^2[2^2*x/2^2+2^3/2^2]
x(x+2)+2^2(x+2)=0
(x+2)(x+4)=0
x+2=0
x+4=0
x=-2
x=-4