Question 813584
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Hi,
Evaluate the derivative of y = tan(4x+1)
Using the Chain Rule: y '=  {{{(dy/du) (du/dx)}}}
Let u = (4x+1), {{{(du/dx) = 4}}}
y = tan(u)
y' = {{{(dy/du) (du/dx)}}}= 4sec^2(u)
y ' = 4sec^2(4x+1)  |  u = (4x+1)