Question 68788
a chemist wants to make a 10% solution of fertilizer. How much water and how much of a 30% solution should the chemist mix to get 30 L of a 10% solution?
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Let amount of 30% solution be "x" L ; amt. of active ingredient=0.30x L
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Amt. of 0% solution is "30-x" L; amt. of active ingredient = 0(30-x)=0 L
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Amt of mixture is 30 L ; amt of active ingredient = 0.10(30)= 3 L
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EQUATION:
active + active = active
0.30x + 0 = 3
x=10 L (He should add 10 L of 30% solution)
30-x=20L (He should add 20 L of water)
Cheers,
stan H.