Question 812984
what are the first three x intercepts of f(x)=2sin(x+Pi/4)
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f(x)=2sin(x+π/4)
set f(x)=0
2sin(x+π/4)=0
sin(x+π/4)=0=sin(0)=sin(π)=sin(2π)=sin(3π)
..
x+π/4=0
x=-π/4≈-0.78
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x+π/4=π
x=π-π/4=3π/4≈2.35
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x+π/4=2π
x=2π-π/4=7π/4≈5.49
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x+π/4=3π
x=3π-π/4=11π/4≈8.64
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first three x intercepts:2.35, 5.49, 8.64