Question 813096
Find the set of values of x (in radians) for which sec(x) = sqrt(2), for x in [0, 2&#960;].
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secx=&#8730;2
cosx=1/&#8730;2=&#8730;2/2
x=&#960;/4, 7&#960;/4 (In quadrants I and IV where cos>0 and sec>0)