Question 68753
I understand the function of a domain when f(x) is given along with the equation, but I do not understand how to find the domain of the function.
look for critical points of x ..like division by zero, square root of 
negative number etc...which makes the operation in admissible. they 
are to be eliminated from domain .hence domain is all real numbers except 
those critical points.
f(x)=1-2x^2
there is no critical point. hence domain is all real values
f(x)=3^sqrt y-10
here sqrt(x-10) is involved.hence domain is all real values of x except
x<10
f(x)=4^sqrt x+1/x-2
same way (x+1)/(x+2)should be >=0....x=-1....or.....
both x+1 and x+2 should be +ve...hence x>-1
or
both x+1 and x+2 should be -ve....hence x<-2
hence domain is 
x=-1,x>-1,x<-2
x=[-1,infinity)U(-infinity,-2)








Thank you for your help!!!!!
Christopher