Question 812848
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Hi,
The perimeter of a rectangular parking lot is 146 yards what is the dimensions 
if the length is 7 yards less than 4 times the width
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Let x represent the width and (4x-7)the length 
Question states***
 146 = 2(4x-7) + 2x
Solving for x
   10x = 160
     x = 16 yd, the width and the length is 57 yds
CHECKING our Answer***
  114yd + 32yd = 146yd