Question 812809
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Hi,
 sum of three numbers is 2008
Let x represent the first number
the second is 2 less than twice the first 0r  2x-2
 the third is 9 more than thrice the second  0r 3(2x-2) + 9

 x + (2x-2) + 3(2x-2)+9 = 2008   ***
   9x +1 = 2008
      9x = 2007
       x = 223
Numbers are 223, 444, 1341

CHECKING our Answer***
 223 + 444 + 1341 = 2008