Question 812758
{{{w}}}= the width of the rectangle, in inches
{{{w+4}}}= the length of the rectangle, in inches
For a rectangle,
{{{perimeter=length+width+length+width}}},
or {{{perimeter=2length+2width}}}
or {{{perimeter=2(length+width)}}},
so we can calculate it many ways.
I'll pick one, but all ways would lead to the same {{{4w+8}}} expression.
{{{perimeter=2w+2(w+4)}}}
My first equation would be
{{{2w+2(w+4)=96}}}
{{{2w+2w+8=96}}}
{{{4w+8=96}}}
{{{4w+8-8=96-8}}}
{{{4w=88}}}
{{{4w/4=88/4}}}
{{{w=22}}}
That means that the width is 22 inches, so the length must be 26 inches, because
{{{w+4=22+4}}} --> {{{w+4=26}}}
So, the area must be
{{{(22inches)(26inches)=highlight(572)}}}{{{square}}}{{{inches}}} .