Question 812712
100$ is put into an account that earns 3.5% interest compunded annually. How much would be in the account after 10 years? 
A(10) = 100(1+(0.035/1))^(1*10) = 100(1.035)^10 = $141.06
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Also how long would it take for the account to have $200? 
Solve for "t":
200 = 100(1.035)^t
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2 = 1.035^t
t = log(2)/log(1.035)
t = 20.15 years
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Cheers,
Stan H.