Question 9045
assuming you mean {{{sqrt(8x^5y)}}} then we get {{{sqrt(8)sqrt(x^5)sqrt(y)}}} which becomes 


{{{sqrt(4*2)sqrt(x^5)sqrt(y)}}}
{{{sqrt(4)sqrt(2)sqrt(x^5)sqrt(y)}}}
{{{2sqrt(2)sqrt(x^5)sqrt(y)}}}


this is rather untidy, so write it as {{{2sqrt(2x^5y)}}}


I just split everything into separate square roots so you could see the process...but it was only the 8 that we could really do anything with.


jon.