<PRE><B>Question 812336</B>
SIN A =-2/7 AND A IS LIE ON QUADRANT III..
WHAT IS THE VALUE OF TAN A???
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Note: In QIII, x is negative and y is negative
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Since sin = y/r, y = -2 and r = 7
So, x = -sqrt[7^2-2^2] = -sqrt(45) = -(3)sqrt(5)

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Your Problem:
tan = y/x
So tan(A) = [-2]/[-(3)sqrt(5)] = (2/3)sqrt(5)/5 = (2/15)sqrt(5)
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Cheers,
Stan H.
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