Question 812249
3x - 6y = 12
2x - 4y = 8 
You don't have to find b or m here, just solve for x and y
Rearrange the first equation so we can use it for substitution in the 2nd equation
3x - 6y = 12
3x = 6y + 12
divide eq by 3
x = 2y + 4
:
substitute (2y+4) for x in the 2nd equation
2(2y+4) - 4y = 8
4y + 8 - 4y = 8
8 = 8, this means there is no unique solution for this system
Many values for x and y will satisfy this system of equations
:
:
 2x + y = 0
 y = 2x - 4
:
Substitute (2x-4) for y in the first equation
2x + (2x-4) = 0
4x = 4
x = 4/4
x = 1
find y
y = 2(1) - 4
y = 2 - 4
y = -2
:
Solution to this one: x=1, y=-2
:
Check solution in the 1st equation
2x + y = 0
2(1) + (-2) =
2 - 2 = 0; confirms our solution here