Question 811770
I am not sure what you meant, but here are 2 interpretations
 
{{{(9^2)(2^3)(3sqrt(2))(27)(-2)}}} = {{{((3^2)^2)(2^3)(3*2^0.5)(3^3)(-2)}}}
= {{{-(3^4)(2^3)(3*2^0.5)(3^3)(2)}}}
= {{{-(3^4)(2^3)(3)(2^0.5)(3^3)(2)}}} = {{{-(2^3*2*2^0.5)(3^4*3*3^3)}}}
= {{{-(2^(3+1+0.5))(3^(4+1+3))}}} = {{{-2^4.5*3^8}}}
 
{{{(9^2)(2^3)(3sqrt(2))(27^(-2))}}} = {{{((3^2)^2)(2^3)(3*2^0.5)((3^3)^(-2))}}}
= {{{(3^4)(2^3)(3*2^0.5)(3^(-6))}}} = {{{(2^3*2^0.5)(3^4*3*3^(-6))}}}
= {{{2^3.5*3^(4+1-6)}}} = {{{2^3.5*3^(-1)}}} = {{{2^3sqrt(2)/3}}}
 
I had to write {{{2^0.5}}}} with {{{0.5}}} as an exponent instead of {{{1/2}}} 
because {{{2^(1/2)}}} does not show properly.
 
NOTE: You can write 2^3 for {{{2^3}}} and sqrt(2) for {{{sqrt(2)}}} and we will understand it. Those are common ways to write exponents and square roots.
Other roots, like {{{root(3,27)}}} are trickier. Although many of us would recognize "root(3,27)" as meaning {{{root(3,27)}}}, that is not as commonly understood.