Question 811725

{{{2y+x=9}}} ........eq.1

{{{x=3y-3}}}.....eq.2
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{{{2y+x=9}}} ........eq.1......substitute {{{x}}} from eq.2

{{{2y+3y-3=9}}}.....solve for {{{y}}}

{{{5y=9+3}}}

{{{5y=12}}}

{{{y=12/5}}}

{{{highlight(y=2.4)}}}

now, go back to {{{x=3y-3}}}.....eq.2, substitute {{{2.4}}} for {{{y}}} and solve for {{{x}}}

{{{x=3*2.4-3}}}.....eq.2

{{{x=7.2-3}}}

{{{highlight(x=4.2)}}}