Question 811656
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Given: m&#8736;ADB not equal m&#8736;BDC Prove: -->(ray) DB  is not the bisector of &#8736;ADC

{{{drawing(200,175,-2,14,-7,7,

line(0,0,10,5),line(0,0,10,-5), line(0,0,16,2), 
locate(-.4,0,D), locate(10,5,A), locate(12,3,B), locate(10,-5,C),
circle(12,1.5,.2), circle(12,1.5,.15), circle(12,1.5,.12), circle(12,1.5,.08), circle(12,1.5,.05) )}}} 
                                        ->
1.  Assume, for contradiction, that ray DB is the bisector of &#8736;ADC
2.  m&#8736;ADB = m&#8736;CDB  (definition of angle bisector)
3.  Contradiction to what we are given:  m&#8736;ADB not equal m&#8736;BDC 

Edwin
PS.  Do not use < for &#8736; because the computer thinks it is the beginning
of an HTML tag and deletes what comes after it. The code for the angle symbol
&#8736; is & #8736; without the space between the & and the #.

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