Question 811700

{{{x^2+7x+4=0 }}}.....use quadratic formula


{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}...in your case {{{a=1}}},{{{b=7}}} and {{{c=4}}}


{{{x = (-7 +- sqrt( 7^2-4*1*4 ))/(2*1) }}}


{{{x = (-7 +- sqrt( 49-16 ))/2}}}


{{{x = (-7 +- sqrt( 33 ))/2}}}


{{{x = (-7 +- 5.75)/2}}}


solutions:

{{{x = (-7 +5.75)/2}}}

{{{x = -1.25/2}}}

{{{x = -0.625}}}

or

{{{x = (-7 -5.75)/2}}}

{{{x = -12.75/2}}}

{{{x = -6.375}}}


{{{ drawing( 600, 600, -10, 10, -10, 10, circle(-0.625,0,0.2), circle(-6.375,0,0.2),graph( 600, 600, -10, 10, -10, 10,x^2+7x+4)) }}}