Question 811563
Use of quadratic formula solution is merely plugging-in values from the given equation.  


Putting (the first one) into "vertex" form, or Standard Form, is a different process.  Complete The Square!


{{{y=x^2+4x-6}}} as given.  The missing square term to use is {{{(4/2)^2=4}}}.
'
{{{y=(x^2+4x+4-6-4)}}}
{{{y=((x^2+4x+4)-10)}}}
{{{highlight(y=(x+2)^2-10)}}}---------------DONE.