Question 811490
discribe and sketch the conic x^2+4y+8x+4=0
x^2+8x+16 = -4y-4+16
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(x + 4)^2 = -4y + 12
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-4(y-3) = (x+4)^2
y = (-1/4)(x+4)^2 + 3
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{{{graph(400,400,-10,10,-10,10,(-1/4)(x+4)^2+3)}}}
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vertex at (-4,3)
parabola opening downward
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Cheers,
Stan H.
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