<PRE><B>Question 811484</B>
given y = 3x/2 -4
1)  parallel lines have the same slope, therefore a line parallel to the given line and passes through the point (3,6) is
6 = (3/2)*3 +c
12/2 = 9/2 +c
c = 3/2
y = 3x/2 +3/2
here is the graph of the parallel lines
{{{ graph( 300, 200, -10, 10, -10, 10, 3x/2 -4, 3x/2 +3/2) }}}
2) the product of the slopes of two perpendicular lines is negative one, therefore
3/2 * m = -1 and m is -2/3, consider that this new line passes through point (3,6)
6 = (-2/3)*3 +c
c = 8
y = -2x/3 +8
here is the graph of the perpendicular lines
{{{ graph( 300, 200, -10, 10, -10, 10, 3x/2 -4, -2x/3 +8) }}}

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