Question 811484
consider the line y=3/2x-4 
Find the equation of the line that is parallel to this line and passes through the point (3,6)?
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The given line has slope = 3/2
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Any line parallel to it must have slope = 3/2
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Form: y = mx + b
Solve for "b":
6 = (3/2)3 +b
12/2 - (9/2) = b
b = 3/2
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Equation:
y = (3/2)x + (3/2)
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Find the equation of the line that is perpendicular to this line and passes through the point (3,6)?
Any line perpendicular to the given line must have slope = -2/3
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Form: y = mx+b
Solve for "b":
6 = (-2/3)3 + b
b = 6 +2
b = 8
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Equation:
y = (-2/3)x + 8
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Cheers,
Stan H.
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