Question 811202
ind a quadratic equation whose roots differ by 1
a, b
a = b + 1 
and are reciprocals of each other.
a = {{{1/b}}}
then
b + 1 = 1/b
mult by b
b^2 + b = 1
b^2 + b - 1 = 0
Using the quadratic formula:
b = -1.618
b = +.618
Using the positive solution: a = 1.618
FOIL
(x+.618)(x+1.618) = x^2 + 2.236x  + 1
Two roots using the quadratic formula:
x = -1.618
x = -.618
:
Check on calc 1/1.618 = .618, and 1/.618 = 1.618