Question 68674
{{{x^2+3x-1=0}}}

Use Quadratic Formula: {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
<br.
{{{ax^2+bx+c = 0}}}
{{{x^2+3x-1=0}}}, a = 1, b = 3, c = -1
{{{x = (-3 +- sqrt( 3^2-4*1*-1 ))/(2*1) }}}
{{{x = (-3 +- sqrt( 9+4 ))/(2)}}}
{{{x = (-3 +- sqrt(13))/(2)}}}
{{{x = -3/2 +- sqrt(13)/2}}}
<br> You got it correct