Question 811241
{{{log(6,x)+log(6,(x+5))=2}}}
adding 2 logs together is the same as the product of the log.
{{{loga+logb=logab}}}
{{{log(6,x)+log(6,(x+5))=2}}}
{{{log(6,x(x+5))=2}}}
turn the log into an exponential.
{{{log(a,c)=b}}}
{{{a^b=c}}}
{{{log(6,x(x+5))=2}}}
{{{6^2=x(x+5)}}}
{{{36=x^2+5x}}}
{{{x^2+5x-36=0}}}
now simply factor
{{{(x+9)(x-4)=0}}}
x=-9,4