Question 811209
A diagram would probably help.
Let h = time in hours when the cars are 300 km. apart.  The starting point location is the right angle vertex of a triangle.


{{{(50h)^2+(60h)^2=300^2}}}
{{{h^2(2500+3600)=300^2}}}
{{{h^2=(300^2)/6100}}}
{{{h=300/(10*sqrt(61))}}}
{{{h=30/(sqrt(61))}}}
{{{h=3.84}}} as a simple decimal approximation, in hours.


The eastward car traveled 50*3.84=192 km.
The southward car traveled 230 km.