Question 811052
If sec t = 5/4 with C(t) in quadrant 4, determine csc(t+pie).
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Note: In QIV x is positve and y is negative
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Since sec(t) = r/x = 5/4, r = 5 and x = 4
Then y = sqrt[5^2-4^2] = -3
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Your Problem:
csc(t+pi) = -csc(t) = -y/r = 3/5
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Cheers,
Stan H.