Question 811158
<pre>
y = a·sin[b(x+c)] + d  or y = a·cos[b(x+c)] + d   

amplitude = |a|
period = {{{2pi/b}}}
horizontal shift = |c| right if c negative, left if c positive
vertical shift = |d| up if d positive, down if d negative

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y = 5·cos(5t+13) &#8722; 4

y = 5·cos[5(t+{{{13/5}}})] - 5 

a=5, b=5, c={{{13/5}}}, d = -5  

amplitude = |5| = 5
period = {{{2pi/5}}}
horizontal shift = |13/5| = 13/5 left since c positive
vertical shift = |-5| = 5 down since d negative

Edwin</pre>