Question 811078
divide the equation into 2 parts.
{{{xy-3x}}}
{{{2y-6}}}
now factor each part.
{{{x(y-3)}}}
{{{2(y-3)}}}
now put them back together.
{{{x(y-3)+2(y-3)}}}
They both have the same stuff in the ( ) so this becomes {{{(x+2)(y-3)}}}