Question 811058
{{{-2x+4y=10}}}
{{{2x-5y=-14}}}
We are going to solve the first problem for x.
{{{-2x+4y=10}}}
{{{-2x=-4y+10}}}
{{{x=2y-5}}}
plug this equation into the second equation. x can be substituted for 2y-5.
{{{2(2y-5)-5y=-14}}}
{{{4y-10-5y=-14}}}
{{{-y-10=-14
{{{-y=-4}}}
{{{y=4}}}
Now we know what y is, so plug this into either equation to find x.
{{{-2x+2(4)=10}}}
{{{-2x+8=10}}}
{{{-2x=2}}}
{{{x=-1}}}
The solution is (-1,4). This is the point where these 2 lines cross.