Question 810870
angle of projection = 37 deg

calculate the time taken to reach a height of 25 m
The vertical component is v sin {{{Theta}}}

y=25=ut+1/2 (-g)t^2 where t is the time in seconds

25=30t-1/2*9.8t^2

4.9t^2-30t+25=0

t= 5.13 & 1

in the horizontal direction d=rt

d=v cos{{{Theta}}}*t
=v cos 37 *1
=39.9 meters
OR
d=vcos 37 * 5.13
=204.85 meters