Question 810783
a) P(at least 1 bad egg) = 1-P(no bad eggs) = 1- (9C3)/(12C3) = 1-84/220

= 1- 21/55 = 34/55

Answer: 34/55

b) P(2 bad eggs) =  (3C2)(9C1)/(12C3) = 27/220 

ANswer:  27/220

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