Question 810800
Boat A leaves the pier at 9 a.m. at 8 Knots. A half hour later, Boat B leaves the same pier in the same direction traveling at 10 knots. At what time will Boat B overtake Boat A?
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Boat A DATA::
rate = 8 kt/hr ; time = x hrs ; distance = 8x kts
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Boat B DATA:
rate = 10 kt/hr ; time = x-1/2 hrs ; distance = 10(x-(1/2)) = 10x-5
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Equation:
distance = distance
8x = 10x-5
2x = 5
x = 2.5 hrs
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Your Problem:
9:00 + 2.5 hrs = 11:30
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Cheers,
Stan H.
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