Question 809915
{{{a[1]=16}}}
{{{a[n]=112}}}
{{{d=22-16=6}}}


{{{a[n]=a[1]+(n-1)d}}}


{{{112=16+(n-1)*6}}}

{{{n=(112-16)/6+1=17}}}



{{{S[n]=(n/2)(a[1]+a[n])}}}


{{{S[n]=(17/2)(16+112)=1088}}}