Question 810597
If I have to count from 101 to 999, it'd take a lot of effort to extract those palindromes. Here's what you should do.

Since you know what palindromes are, count how many you can find between (and including) 101 and 999.

Then you go n(P)/n(T)
*n(P) - possible outcomes
*n(T) - total number of outcomes

n(T) is 900 (there're 900 three-digit numbers!)

so n(P)/900 is your answer.

PSSST! I just checked. They each (1 through 9) have 10 palindromes. Total of 90.
So your answer should be 90/900, which is 1/10!

Thanks for the challenge!