Question 810547
Given that x is a normal variable with mean u = 47 and standard deviation = 6.2, find:
(A) P(x ≤ 120) 
z(120) = (120-47)/6.2 = 11.77
P(x < 120) = P(z < 11.77) = 1
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Use the same procedure on B and C.
Cheers,
Stan H.
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(B) P(x &#8805; 80), (C) P (108 &#8804; x &#8804; 117)