Question 810118
find the range of the function.
h(x)=x^2/(1-x^2)
***
Vertical asymptotes:
set denominator=0, then solve for x
1-x^2=0
(1+x)(1-x)=0
x=-1 and x=1
..
Horizontal asymptotes:
When degree of denominator=degree of numerator, divide their coefficients, 1/-1=-1
y=-1
...
number line:
<..-..-1..+..0..+..1..-..>
ans: d. (- &#8734;, -1) U [0, &#8734; )

see graph below:

{{{ graph( 300, 300, -10, 10, -10, 10,x^2/(1-x^2)) }}}