Question 810391
how would you solve sin(cos-1(x/6))
sin(cos^-1(x/6)
reads: sin of cos inverse(x/6)
sin=√(1-cos^2)=√(1-(x^2/36))={{{sqrt((36-x^2)/36)}}}
sin(cos^-1(x/6))={{{sqrt(36-x^2)/6}}}