Question 810322
{{{log(x+4)+log(x)=9}}}
{{{log((x+4)x)=3^2}}}
If your base chosen is 3, then form the exponential equivalent to the equation, 


{{{3^(3^2)=(x+4)x}}}


{{{3^9=x^2+4x}}}
{{{x^2+4x-3^9=0}}}


{{{x=(-4+- sqrt(16+4*3^9))/(2)}}}
{{{x=(-4+- 2*sqrt(1+3^9))/(2)}}}
{{{highlight(x=-2+- sqrt(1+3^9))}}} or {{{highlight(x=-2+- sqrt(196684))}}}