Question 809783
Graph Y > x^2-4x+5
How do I find the points to graph?
y=x^2-4x+5
complete the square
y=(x^2-4x+4)-4+5
y=(x-2)^2+1
vertex:(2,1)
parabola opens up
y-intercept: set x=0
y=5
axis of symmetry:x=2
point(4,5)
x-intercepts:none (from vertex)
This should give you enough points to graph the parabola
See graph below:
{{{ graph( 300, 300, -10, 10, -10, 10,  x^2-4x+5) }}}