Question 68515
An architect has designed a motel pool within a rectangular area that is fenced on three sides. If she uses 60 yards of fencing to enclose an area of 352 square yards, then what are the dimensions of the fence. (L and W) Assume L is greater than W.
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Draw the picture of a rectangular area with a motel on one side.
Let the 3-sided fence have perimeter = 2(width)+(length)= 60
and Area = (length)(width)=352 sq yds.
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EQUATIONS:
 L+2W=60
 L=60-2W
Area=LW=(60-2W)W=352
-2W^2+60W=352
w^2-30w+176=0
(W-22)(W-8)=0
W=8 yds. (if L is to be greater than W).
L=60-2W =60-16 =44 yrds
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Cheers,
Stan H.