Question 808770
Given:
(1) cos(4x)cos(2x) + sin(4x)sin(2x) = sqrt(3)/2
Use the difference formula
(2) cos(a-b) = cos(a)cos(b) + sin(a)sin(b) to obtain
(3) cos(4x - 2x) = cos(4x)cos(2x) + sin(4x)sin(2x)
Now equate (1) and (3) to get
(4) cos(4x - 2x) = sqrt(3)/2 or
(5) cos(2x) = sqrt(3)/2
Use your calculator to evaluate
(6) 2x = arccos(sqrt(3)/2) and get
(7) 2x = 30 or
(8) x = 15 degrees
This is also the solution at 
(9) x = 15+180 or
(10) x = 195 degrees
Answer: x = {15,195} degrees