Question 808530
 log(x+1)+log(x-1)=log(3)
:
 log((x+1)(x-1)) = log(3)
therefore 
(x+1)(x-1) = 3
FOIL
x^2 - x + x - 1 = 3
x^2 - 1 - 3 = 0
x^2 - 4) = 0
Factors to
(x-2)(x+2) = 0
only the positive solution here
x = 2