Question 808542
Simple method, if y=F(x), try making {{{x=(3/4)y-5/6}}} and solve for y.  If this method, y will no longer be F(x), but some other name of function.


{{{x+5/6=(3/4)y}}}
{{{(4/3)(x+5/6)=y}}}
{{{y=(4/3)x+(4/3)(5/6)}}}
{{{y=(4/3)x+(2/3)(5/3)}}}
{{{y=(4/3)x+10/9}}}


Meaning, {{{highlight(F^-1(x)=(4/3)x+10/9)}}}