Question 808442
Try to think your way through the process described.


16 gallons of regular;
17 miles per gallon.
Want "mixture" to become 95% premium gasoline, so how much room needs to be in the tank to do this?  Review that information and think, before continuing...


The 16 gallons of regular is thought to be as 0% premium.  You may start this through "algebra".  v = how much to remove and replace with premium to get 95% premium:


{{{(16*0-v*0+v*100)/16=95}}}
{{{v*100/16=95}}}
{{{v=95*16/100}}}
{{{v=15.2}}} gallons.


The old chevy must consume 15.2 gallons of the regular gasoline and replace it with the premium gasoline to obtain the mixtures of 95% premium... but how many MILES correspond to this 15.2 miles?


Use the fuel efficiency datum.
{{{(15.2)*(17)}}} {{{gallons(miles/gallons)}}}
{{{highlight(258)}}} MILES as a target value, minumum.