Question 808176
y+3 = 2x

y=2x-3

x^2 +2xy = -1

x^2+2xy+1=0

(x+y)^2=0

substitute y

(x+2x-3)^2=0

(3x-3)^2=0

9(x-1)^2=0

(x-1)^2=0

x-1=0
x=1

y+3=2x
x=1
y+3=2
y=-1

x=1,y=-1