Question 68412
I.What is Ask in the problem? 
--> How much does she have invested in each account?
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Given :
--> One money is a market account paying 9.5%
--> The other is a cd that pays 12% interest
--> Total money invested is $ 25,000
--> Barb receives $ 2,700 interest from these combined investments after a year
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Representation:
Let x = the money invested in the market account that  gets 9.5% interest
    y = the money cd that pays 12% interest
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Equations: 
1. x + y = $ 25,000
2. 0.095x + 0.12y = $ 2,700 
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Solution:
A. <i> Note: I can multiply the equation 2 by 1000 so that I won't deal with decimals.</i>
   95x + 120y = 2, 700,000
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B. Write the two equation and solve.
   x +    y = $     25, 000
 95x + 120y = $ 2, 700, 000
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C. Multiply -95 to x + y = $ 25,000 to eliminate x
 -95x - 95y  = -$ 2, 375, 000
  95x + 120y = $ 2, 700, 000
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D. Add the two equations
   25y = $ 325, 000

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E. Divide both sides by 25
  y = $ 13, 000 money cd that pays 12% interest

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F. Substitute $ 13, 000 to y to any of the two equation
x + y = $ 25, 000
x + $ 13, 000 = $ 25, 000
x = $ 12, 000 money invested in the market account with 9.5% interest

Checking:
1.
x + y = $ 25, 000
$ 13, 000 + $ 12, 000= $ 25, 000
$25, 000 = $ 25, 000 ---------> True

2. 0.95x + 0.12y = $ 2,700

  $ 1, 140 + $ 1, 560= $ 2, 700
$ 2, 700 = $ 2, 700 ------------>True

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Therefore the money invested in the market account is $ 12, 000 and the money cd is $ 13, 000.