Question 808017
(k+4)x^+(k+1)x+1=0 has equal roots. 

in the quadratic equation ax^2 +bx +c the roots are equal when
the discriminant b^2-4ac = 0

comparing the equation

a= (k+4) b= (k+1) c=1

(k+1)^2-4(k+4)(1)=0

k^2+2k+1-4k-16=0

k^2-2k-15=0

k^2-5k+3k-15=0

k(k-5)+3(k-5)=0

(k-5)(k+3)=0

k- +5 OR k-3