Question 807941
Find the exact values of theta on the interval [0degrees, 360 degrees) that make the following equation a true statement.
3 sin theta- 6 sin theta cos theta cos theta =0
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use x for theta
{{{3sin(x)-6sin(x)cos(x)cos(x)=0}}}
(3sinx)(1-2cos^2x)=0
(3sinx)(1-2(1-sin^2x)=0
(3sinx)(1-2+2sin^2x)=0
(3sinx)(-1+2sin^2x)=0
..
3sinx=0
x=0, 180˚
..
-1+2sin^2x)=0
sin^2x=1/2
sinx=±1/√2=±√2/2
x=45˚, 135˚, 225˚, 315˚