Question 807906
{{{ 2*log(( x-1 )) = 2 + log( 100 ) }}}
Note that {{{ log( 100 ) = 2 }}}, so
{{{ 2*log(( x-1 )) = 2 + 2 }}}
{{{ 2*log(( x-1 )) = 4 }}}
{{{ log(( x-1 )) = 2 }}}
{{{ 10^2 = x - 1 }}}
{{{ x - 1 = 100 }}}
{{{ x = 101 }}}