Question 807881
Why doesn't 256 r^2 + 289 = 0 have a real solution? And why can't it be solved using factorization?
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256*r^2 + 289 = 0
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256*r^2 = -289
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Since the right side is negative, r^2 must be negative.
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But there is no Real Number whose square is negative.
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Note: The equation is solvable using complex numbers.
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Cheers,
Stan H.